2x^2+4x+80=0

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Solution for 2x^2+4x+80=0 equation: 



2x^2+4x+80=0

a = 2; b = 4; c = +80;
Δ = b2-4ac
Δ = 42-4·2·80
Δ = -624
Delta is less than zero, so there is no solution for the equation

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